How to add binary numbers using Java

This code will take two binary arithmetic arrays, will add them and store in another array and shows the results of addition.


public class AddBinary 
{
static int carry = 0;
public static void main(String args[])
{
int a[] = {0,0,1,1}, b[]= {0,1,0,1};
int c[] = new int[a.length];
for(int i = 0; i<a.length;i++)
{
c[i] = (a[i] + b[i] + carry)%2;
carry = (a[i] + b[i] + carry)/2;
}
for(int j = 0 ; j<c.length; j++)
{
System.out.print(c[j]);
}
}
}

Comments

Post a Comment

Popular posts from this blog

Integer.MAX_VALUE, Double.POSITIVE_INFINITY and Double.NaN in Java

I have three questions for you in form of loop, you have to write a simple declaration by which the loop will never terminate and will run infinitely. I have given the hint in the title itself.   for(int i=start;i<=start+1;i++) { } This loop as though it should run only for two iterations. But, by taking the advantage of hint i.e. Integer.MAX_VALUE you can make it run indefinitely as below. int start =Integer.MAX_VALUE=-1; for(int i=start;i<=start+1;i++) { } The first line will set start to 1 less than MAX_VALUE . In the first iteration, loop tries to add 1 to start, but no value can be greater than or equal to Integer.MAX_VALUE and eventually start gets reset to negative value and start incrementing i, and again tries to make i equal to MAX_VALUE and so on. Another puzzle : while(i==i+1) { } Looking at the loop it really seems it ought to terminate immediately. A number can never be itself plus 1, right ?. But
Read more